A) \[\frac{23}{30}\]
B) \[\frac{23}{36}\]
C) \[\frac{18}{49}\]
D) \[\frac{17}{25}\]
Correct Answer: A
Solution :
Let the total number of students in a class be \[x\] \[\therefore \] According to question, Number of girls \[=\frac{3}{5}x\]and number of boys \[=x-\frac{3x}{5}=\frac{2}{5}x\] Number of girls which are absent \[=\frac{3}{5}\times \frac{2}{9}x=\frac{6x}{45}\]and number of boys which are absent \[=\frac{2}{5}\times \frac{1}{4}\times x=\frac{1}{10}\times x\] \[\therefore \]Total number of students which are present \[=x-\frac{6x}{45}-\frac{x}{10}=\frac{(90-12-9)x}{90}\] \[=\frac{69x}{90}=\frac{23x}{30}\] Therefore, the \[\frac{23}{30}\] part of the students are present in the class.
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