A) \[1:16\]
B) \[1:64\]
C) \[1:4\]
D) \[1:128\]
Correct Answer: B
Solution :
Given that, the diameter of Moon is approximately one-fourth of the diameter of Earth. If radius of the Moon = r, then radius of the Earth = 4r, Now \[\frac{Volume\text{ }of\text{ }Moon}{Volume\text{ }of\text{ }Earth}\] \[=\frac{\frac{4}{3}\pi {{r}^{3}}}{\frac{4}{3}\pi {{(4r)}^{3}}}=\frac{{{r}^{3}}}{64{{r}^{3}}}=\frac{1}{64}=\]
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