A) \[-2\]
B) \[-1\]
C) \[0\]
D) \[1\]
Correct Answer: C
Solution :
\[\because \,\,\,5\sin \theta +12\cos \theta =13\] On squaring both sides, we get \[25{{\sin }^{2}}\theta +144{{\cos }^{2}}\theta +120\sin \theta \,\,\cos \theta =169\] \[25\left( 1-{{\cos }^{2}}\theta \right)+144\,\left( 1-{{\sin }^{2}}\theta \right)\] \[+120\sin \theta \,\,\cos \theta \,=169\] \[25\,{{\cos }^{2}}\theta +144\,{{\sin }^{2}}\theta \] \[-120\sin \theta \,\cos =169-169\] \[{{(5\,\cos \theta -12\,\sin \theta )}^{2}}=0\] \[5\cos \theta -12\sin \theta =\]
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