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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-11

  • question_answer
    If \[x-\frac{1}{x}=\frac{1}{3},\]then what is \[9{{x}^{2}}+\frac{9}{{{x}^{2}}}\]equal to ?

    A)  18                              

    B)  19

    C)  20                              

    D)  21

    Correct Answer: B

    Solution :

     \[9{{x}^{2}}+\frac{9}{{{x}^{2}}}\] \[=9\,\left( {{x}^{2}}+\frac{1}{{{x}^{2}}} \right)=9\left[ {{\left( x-\frac{1}{x} \right)}^{2}}+2 \right]\] \[=9\left[ {{\left( \frac{1}{3} \right)}^{2}}+2 \right]=9\times \frac{19}{9}=\]


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