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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-12

  • question_answer
    If \[4\,\tan \theta =3,\] then what is \[\frac{4\sin \theta -\cos \theta }{4\sin \theta +9\cos \theta }\] equal to?

    A)  \[\frac{1}{2}\]             

    B)  \[\frac{1}{3}\]

    C)  \[\frac{1}{4}\]            

    D)  \[\frac{1}{6}\]

    Correct Answer: D

    Solution :

     \[\frac{4\,\sin \theta -\cos \theta }{4\sin \theta +9\cos \theta }\] On dividing both numerator and denominator by \[cos\text{ }\theta ,\]we get- \[=\,\,\,\frac{4\tan \theta -1}{4\tan \theta +9}=\frac{3-1}{3+9}=\frac{2}{12}=\]


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