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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-12

  • question_answer
    If  \[\frac{2x-3y+1}{2}=\frac{x+4y+8}{3}=\frac{4x-7y+2}{5}\]then what is \[(x+y)\] equal to ?

    A)  3                                

    B)  2             

    C)  0                                

    D)  \[-2\]

    Correct Answer: D

    Solution :

                \[\frac{2x-3y+1}{2}=\frac{x+4y+8}{3}\] \[\Rightarrow \,\,6x-9y+3=2x+8y+16\] \[\Rightarrow \,\,4x-17y=13\]                    ??.(i) Also, \[\Rightarrow \,\,\frac{2x-3y+1}{2}=\frac{4x-7y+2}{5}\] \[\Rightarrow \,\,\,2x-y=-1\]                                      ??.(ii) On solving (i) and (ii), we have \[x=-1\] and \[y=-1\] \[\Rightarrow \,\,x+y=\]


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