2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-12

  • question_answer
    If \[{{x}^{5}}-9{{x}^{2}}+12x-14\] is divided by \[(x-3),\] what is the remainder?

    A)  \[0\]                           

    B)  \[1\]

    C)  \[56\]                         

    D)  \[184\]

    Correct Answer: D

    Solution :

     \[P(x)={{x}^{5}}-9{{x}^{2}}+12x-14\] is divided by \[(x-3)\] Remainder \[=p(3)\] \[={{3}^{5}}-9\times {{3}^{2}}+12\times 3-14=\]


You need to login to perform this action.
You will be redirected in 3 sec spinner