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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-14

  • question_answer
    If \[\frac{2}{x}+\frac{3}{y}=\frac{9}{xy}\] and \[\frac{4}{x}+\frac{9}{y}=\frac{21}{xy}\] where \[x\ne 0\] and \[y\ne 0,\] then what is the value of \[x+y\]?

    A)  2                                

    B)  3

    C)  4        

    D)  8

    Correct Answer: C

    Solution :

     \[\frac{2}{x}+\frac{3}{y}=\frac{9}{xy},\]multiply both sides by xy \[2y+3x=9\]                              ??(i) \[\frac{4}{x}+\frac{9}{y}=\frac{21}{xy}\Rightarrow 4y+9x=21\]            .?..(ii) Solving equation (i) and (ii)- \[x=1,\,y=3\Rightarrow x+y=1+3=\]                             


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