2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-14

  • question_answer
    If \[x-\frac{1}{x}=\frac{1}{3}\]. then what is \[9{{x}^{2}}+\frac{9}{{{x}^{2}}}\]equal to?

    A)  18                               

    B)  19

    C)  20                               

    D)  21

    Correct Answer: B

    Solution :

     \[x-\frac{1}{x}=\frac{1}{3},\] Multiply both sides by \[3x-\frac{3}{x}=1\Rightarrow 9{{x}^{2}}+\frac{9}{{{x}^{2}}}-2.3x.\frac{3}{x}=1\] \[\Rightarrow \,\,9{{x}^{2}}+\frac{9}{{{x}^{2}}}=1+18=\]


You need to login to perform this action.
You will be redirected in 3 sec spinner