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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-17

  • question_answer
    The least number which when divided by 48, 64, 90, 120 will leave remainders 38, 54, 80, 110 respectively, is -

    A) 2870                            

    B) 2860

    C) 2890                            

    D) 2880

    Correct Answer: A

    Solution :

    Common difference \[=48-38=10\] Now, find out the LCM of 48, 64, 90 and 120 = 2880 Require number \[=2880-10=\mathbf{2870}\]


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