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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-17

  • question_answer
    If A, B, C and D are four consecutive odd integers and their average is 42 then, What is the product of B and D?

    A) 1860                            

    B) 1890

    C) 1845                            

    D) 1677

    Correct Answer: C

    Solution :

     \[A+B+C+D=42\times 4\] \[(x)+(x+2)+(x+4)+(x+6)=42\times 4\] \[4x+12=168\Rightarrow 4x=156\Rightarrow x=39\] \[B\times D=41\times 45=\mathbf{1845}\]


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