A) \[30{}^\circ ,60{}^\circ ,90{}^\circ \]
B) \[35{}^\circ ,55{}^\circ ,90{}^\circ \]
C) \[40{}^\circ ,50{}^\circ ,90{}^\circ \]
D) \[40{}^\circ ,55{}^\circ ,85{}^\circ \]
Correct Answer: A
Solution :
\[30{}^\circ ,\text{ }60{}^\circ ,\text{ }90{}^\circ \] Smallest angle Largest angle \[60{}^\circ \] \[\pi \] \[60{}^\circ \] \[180{}^\circ \] \[1\] \[3\] \[\therefore \,\] Second angle \[=\frac{1+3}{2}=2\] (\[\because \] All angles are in A.P.) \[\therefore \,\,\,\,1+2+3=180{}^\circ \Rightarrow 6=180{}^\circ \] \[\Rightarrow \,\,\,\,\,\,1=30{}^\circ \] \[\therefore \] Ratio of angles \[1:2:3\] So, Angles are \[\underline{\mathbf{30{}^\circ ,}\,\mathbf{60{}^\circ }\,\mathbf{and}\,\,\mathbf{90{}^\circ }}\]respectively.
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