A) 1 cm
B) 2 cm
C) 3 cm
D) 4 cm
Correct Answer: B
Solution :
Area of \[\Delta \text{ }ABC=\frac{1}{2}\times 6\times 8=24\text{ }c{{m}^{2}}\] Area of \[\Delta \text{ OA}C=\frac{1}{2}\times a\times 10=5a\,c{{m}^{2}}\] Similarly area of \[\Delta \,OBC\] and \[\Delta \,OAB\] will be \[4\text{ }a\text{ }c{{m}^{2}}\]and \[\text{3 }a\text{ }c{{m}^{2}}\] respectively. Area of \[\Delta \text{ }ABC\] = Area of \[(\Delta \text{ OAC+}\Delta \,\text{OBC+}\Delta \,OAC)\] \[24=5a+4a+3a=12a=24=a=2\,cm\] Radius of in circle = 2 cmYou need to login to perform this action.
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