SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-1

  • question_answer
    A can do a piece of work in 16 days and B in 24 days. They take the help of C and three together finish the work in 6 days. If the total remuneration for the work is Rs. 400. The amount (in rupees) each will receive, in proportion, to do the work is

    A)  \[A:150,\,\,B:100,\,\,C:150\]  

    B)  \[A:100,\,\,B:150,\,\,C:150\]

    C)  \[A:150,\,\,B:150,\,\,C:100\]

    D)  \[A:100,\,\,B:150,\,\,C:100\]

    Correct Answer: A

    Solution :

     If C alone completes the work in \[x\] days, then             \[\frac{1}{16}+\frac{1}{24}+\frac{1}{x}=\frac{1}{6}\] \[\Rightarrow \]   \[\frac{1}{x}=\frac{1}{6}-\frac{1}{16}=\frac{1}{24}\]             \[=\frac{8-3-2}{48}=\frac{1}{16}\] \[\Rightarrow \]   \[x=16\]days \[\therefore \]Ratio of their remuneration             \[=\frac{1}{16}:\frac{1}{24}:\frac{1}{16}\]             \[=3:2:3\] \[\therefore \]A's remuneration             \[=\frac{3}{8}\times 400=Rs.\,\,150\] B's remuneration\[=\frac{2}{8}\times 400=Rs.\,\,100\] C's remuneration\[=\frac{3}{8}\times 400=Rs.\,\,150\]


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