A) \[1\]
B) \[-1\]
C) \[2\]
D) \[-2\]
Correct Answer: A
Solution :
Given,\[x+\frac{2}{x}=1\] Expression \[=\frac{{{x}^{2}}+x+2}{{{x}^{2}}(1-x)}=\frac{x+1+\frac{2}{x}}{x(1-x)}\] (Dividing numerator ad denominator b\[x\]) \[=\frac{x+\frac{2}{x}+1}{x(1-x)}=\frac{1+1}{x\times \frac{2}{x}}=\frac{2}{2}=1\]You need to login to perform this action.
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