A) \[{{2}^{60}}\]
B) \[{{3}^{48}}\]
C) \[{{4}^{36}}\]
D) \[{{5}^{24}}\]
Correct Answer: B
Solution :
\[{{2}^{60}}\to {{({{2}^{5}})}^{12}}\to {{(32)}^{12}}\] \[{{3}^{48}}\to {{({{3}^{4}})}^{12}}\to {{(81)}^{12}},\,{{4}^{36}}\to {{({{4}^{3}})}^{12}}\to {{(64)}^{12}}\] \[{{5}^{24}}\to {{({{5}^{2}})}^{12}}\to {{(25)}^{12}}\] \[\therefore \] The greatest number is \[\underline{{{\mathbf{3}}^{\mathbf{48}}}}\]
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