SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-22

  • question_answer
    A can do \[\frac{1}{5}\] work in 5 days and B can do \[\frac{1}{6}\] of same work in 5 days. They work together in 5 days. The remaining work now is -

    A)  \[\frac{30}{11}\]                                  

    B)  \[\frac{11}{30}\]                

    C)  \[\frac{19}{30}\]                                  

    D)  \[\frac{30}{19}\]

    Correct Answer: C

    Solution :

     \[\because \]  A does \[\frac{1}{5}\] part of work in 5 days \[\therefore \] Part of work completed by A in one day \[=\frac{1}{25}\] Similarly, Part of work completed by B in one day \[=\frac{1}{30}\]. \[\therefore \]  Part of work completed by both A and B in one day \[=\frac{1}{25}+\frac{1}{30}\]. \[=\,\,\frac{6+5}{150}\times 5=\frac{11}{30}\] \[\therefore \]  Work done by A and B in 5 days                   \[=\,\,\frac{11}{150}\times 5=\frac{11}{30}\] \[\therefore \]  Remaining work \[=1-\frac{11}{30}\] \[=\,\,\,\,\,\frac{30-11}{30}=\underline{\frac{\mathbf{19}}{\mathbf{30}}}\]


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