A) \[289:361\]
B) \[361:289\]
C) \[19:17\]
D) \[17:19\]
Correct Answer: D
Solution :
Let the area of two square are \[289{{x}^{2}}\] and \[361{{x}^{2}}\] \[\therefore \] Side of square \[=\,\,\,\sqrt{289{{x}^{2}}}\] and \[\sqrt{361{{x}^{2}}}\] \[=\,\,\,17x\] and \[19x\] \[\therefore \] Ratio of perimeters \[=\,\,4\times 17x:4\times 19x=\underline{\mathbf{17:19}}\]
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