A) \[\div ,+,\div ,=\]
B) \[+,\div ,\div ,=\]
C) \[\div ,\div ,+,=\]
D) \[\div ,\times ,\div ,=\]
Correct Answer: A
Solution :
Solving from the Choices: [A] Inserting the oprators \[(\div ,\,+,\,\div ,=).\] We get, \[\underline{\mathbf{169\div 13+144-12=25}}\] [Use BODMAS' rule] \[13+12=25\Rightarrow 25=25\] [B] Inserting the oprators \[(+,\div ,\div ,=)\] We get, \[\underline{\mathbf{169\div 13-144\div 12=25}}\] [Use BODMAS rule] \[169+1.08=25\Rightarrow 170.08\ne 25\] [C] Inserting the oprators \[(\div ,\div ,+,=).\] We get, \[169\div 13\div 144\div 12=25\] [Use 'BODMAS rule] \[1872+12=25\Rightarrow 1884\ne 25\] [D] Inserting the oprators \[(\div ,\times ,\div ,=0).\] We get, \[169\div 13\times 144\div 12=25\] [Use 'BODMAS rule] \[156\div 25\]
You need to login to perform this action.
You will be redirected in
3 sec
