SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-23

  • question_answer
    If \[35%\] of \[A=45\]of \[B=\frac{1}{6}\] of C, then \[A:B:C\] is equal to-

    A)  \[90:70:189\]                

    B)  \[99:70:110\]

    C)  \[89:70:180\]                

    D)  \[35:45:97\]

    Correct Answer: A

    Solution :

     35% of \[A=45\]of \[B=\frac{1}{6}\]of C \[\frac{35}{100}\times A=\frac{45}{100}\times B=\frac{1}{6}\] of C \[\therefore \,\,\,\,\,\frac{35}{100}\times A=\frac{45}{100}\times B\] \[A=\frac{9}{7}B\]                    ?. (i) \[\frac{45}{100}\times B=\frac{1}{6}\times C\Rightarrow C=\frac{45\times 6}{100}\times B\] \[C=\frac{270}{100}\times B\,\,\,\Rightarrow \,\,\,C=\frac{27}{10}B\]      ?? (ii) \[A:B:C=\frac{9}{7}B:B:\frac{27}{10}B\] \[=\,\,\,\,\frac{9}{7}:1:\frac{27}{10}=\,\underline{\mathbf{90:70:189}}\]


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