question_answer

Sumit rode his bike 3km towards North, then turned right and rode 2km. Then he turned his left and rode 1km, again he turned left and rode 6km. Finally, he turned left and rode 1km. How far is Sumit with respect of his initial position?

A)  \[8\,km\]                      

B)  \[5\,km\]

C)  \[7\,km\]                      

D)  \[10\,km\]

Correct Answer: B

Solution :

Shortcut: \[AC=\sqrt{C{{B}^{2}}+A{{B}^{2}}}\Rightarrow AC=\sqrt{{{4}^{2}}+{{3}^{2}}}\] \[AC=\sqrt{16+9}\Rightarrow AC=\sqrt{25}\Rightarrow AC=\mathbf{5}\]