SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-24

  • question_answer
    The denominations of a triangle is 9 cm, 40 cm and 41 cm, then find the length of circumcircle of that triangle?

    A) \[21\,cm.\]                    

    B)  \[20.5\,cm.\]

    C)  \[41\,cm.\]                   

    D)  \[40\,cm.\]

    Correct Answer: B

    Solution :

     Let ABC is a right angle triangle   Here, \[AB==40cm.\,\,\,\Rightarrow BC=9cm.\] \[AC=41\text{ }cm\]. \[\therefore \]  Length of radius of circumcircle \[=\,\,\,\,\frac{AC}{2}=\frac{41}{2}=\underline{\mathbf{20}\mathbf{.5}\,\mathbf{cm}\mathbf{.}}\]


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