A) \[400\,g\]
B) \[500\,g\]
C) \[600\,g\]
D) \[800\,g\]
Correct Answer: B
Solution :
Mixture of acid and water = 3 kg \[=\,\,\,~3000\text{ }g\] Quantity of acid in mixture \[=\,\,\,\,3000\times \frac{70}{100}=2100\,g\] Quantity of water in mixture \[=\,\,\,\,3000\times \frac{30}{100}=900\,g\] Let x g water should be added \[\frac{2100}{900+x}=\frac{60}{40}=\frac{3}{2}\] \[\Rightarrow \,\,\,\,2700+3x=4200\] \[\Rightarrow \,\,\,\,3x=4200-2700=1500\] \[\Rightarrow \,\,\,\,x=\frac{1500}{3}=500\] The amount of water need to added \[=\,\,\underline{\mathbf{500}\,\mathbf{g}}.\]
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