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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-25

  • question_answer
    If \[{{q}^{-a}}=\frac{1}{r},\] \[{{r}^{-b}}=\frac{1}{s}\]and \[{{s}^{-c}}=\frac{1}{q},\] then the value of \[abc\]is -

    A)  \[{{(rqs)}^{-1}}\]                    

    B)  \[0\]

    C)  \[1\]                            

    D)  \[r+q+s\]

    Correct Answer: C

    Solution :

     \[{{q}^{-a}}=\frac{1}{r},\,\,r={{q}^{a}}\]                ??(i) \[{{r}^{-b}}=\frac{1}{s},\,\,s={{r}^{b}}\]                              ??(ii) \[{{s}^{-c}}=\frac{1}{q},\,\,q={{s}^{c}}\]                             ??(iii) From equation (iii) -             \[q={{s}^{c}}\]             \[q={{({{r}^{b}})}^{c}}\]             \[q={{r}^{b}}^{c}\]             \[q={{({{q}^{a}})}^{bc}}\]             \[q={{q}^{abc}}\] So, abc= 1


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