A) \[\frac{13}{5}\]
B) \[-\frac{13}{5}\]
C) \[-\frac{12}{13}\]
D) None of these
Correct Answer: B
Solution :
\[\sin \theta =-\frac{12}{13}\]and\[\pi <\theta <\frac{3\pi }{2}\sec \theta \] \[=-\frac{1}{\sqrt{1-{{\sin }^{2}}\theta }}\] \[=-\frac{1}{\sqrt{1-{{\left( \frac{12}{13} \right)}^{2}}}}=-\frac{1}{\sqrt{\frac{25}{169}}}\] \[\sec \theta =-\frac{13}{5}\]
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