A) \[2\frac{2}{5}\]days
B) \[2\frac{2}{11}\]days
C) \[3\frac{3}{7}\]days
D) \[3\frac{2}{5}\]days
Correct Answer: A
Solution :
(A+B)?S 1 day?s work \[=\frac{1}{6}+\frac{1}{8}=\frac{7}{24}\] C?S 1 day's work \[=\frac{7}{24}\] \[\therefore \](B+C)?s 1 day?s work\[=\frac{1}{8}+\frac{7}{24}=\frac{5}{12}\] \[\therefore \]B and C together will complete the work in\[\frac{12}{5}=2\frac{2}{5}\]days
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