A) \[5\]
B) \[7\]
C) \[123\]
D) \[125\]
Correct Answer: D
Solution :
Expression \[=\sqrt[3]{p\left( {{p}^{2}}+3p+3 \right)+1}\] \[=\sqrt[3]{{{p}^{3}}+3{{p}^{2}}+3p+1}\] \[={{\left[ {{(p+1)}^{3}} \right]}^{\frac{1}{3}}}={{\left( p+1 \right)}^{3\times \frac{1}{3}}}\] \[=p+1\] When\[p=124\], \[p+1=124+1=125\]
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