A) \[\frac{-{{\pi }^{c}}}{8}\]
B) \[\frac{{{\pi }^{c}}}{4}\]
C) \[\frac{{{\pi }^{c}}}{7}\]
D) \[\frac{-{{\pi }^{c}}}{7}\]
Correct Answer: A
Solution :
As\[{{180}^{o}}=\pi \] \[\therefore \] \[-{{22}^{o}}\,\,30'=-\left( 22+\frac{1}{2} \right)\] \[=-{{\left( \frac{45}{2} \right)}^{o}}\] \[=-{{\left( \frac{45}{2}\times \frac{\pi }{180} \right)}^{c}}=-\frac{{{\pi }^{c}}}{8}\]
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