A) \[4\frac{1}{2}\]
B) \[4\]
C) \[5\frac{1}{2}\]
D) \[5\]
Correct Answer: A
Solution :
Time and speed are inversely proportional. \[\therefore \]\[\frac{4}{3}\]of usual time - usual time \[=\frac{3}{2}\] \[\Rightarrow \]\[\frac{1}{3}\times \]usual time\[=\frac{3}{2}\] \[\therefore \]Usual time\[=\frac{3\times 3}{2}=\frac{9}{2}\] \[=4\frac{1}{2}\]hoursYou need to login to perform this action.
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