A) 4
B) Rs. 700
C) Rs. 710
D) 5
E) 6
F) 8
Correct Answer: A
Solution :
The greatest number N = HCF of\[(1305-x),\,\,(4665-x)\] and \[(6905-x)\], where \[x\] is the remainder = HCF of (4665 - 1305), (6905 - 4665)and (6905 - 1305) = HCF of 3360, 2240 and 5600 Again, \[\therefore \]\[N=1120\] Sum of digits \[=1+1+2+0=4\]You need to login to perform this action.
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