A) 3.696 kg
B) 3.6 kg
C) 36 kg
D) 36.9 kg
Correct Answer: A
Solution :
The pipe can be assumed as hollow cylinder. External radius\[=\frac{8}{2}=4\,\,cm\]. Thickness \[=1\,\,cm\] \[\therefore \]Internal radius\[=4-1=3\,\,cm\]. Volume of the material \[=\pi h({{R}^{2}}-{{r}^{2}})\] \[=\frac{22}{7}\times 21\times \left( {{4}^{2}}-{{3}^{2}} \right)\] \[=\frac{22}{7}\times 21\times 7\] \[=462\,\,c{{m}^{3}}\] Now, \[1\,\,c{{m}^{3}}\] iron weighs\[=8\,\,gm\] \[\therefore \]\[462\,\,c{{m}^{3}}\]iron weighs \[=462\times 8\,\,gm=\frac{462\times 8}{1000}kg\] \[=3.696\,\,kg\]You need to login to perform this action.
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