A) \[15\sqrt{2}\,\,cm\]
B) \[15\,\,cm\]
C) \[15\sqrt{5}\,\,cm\]
D) \[15\sqrt{3}\,\,cm\]
Correct Answer: D
Solution :
\[\angle BAC={{60}^{o}}\] \[\therefore \] \[\tan {{60}^{o}}=\frac{BC}{AB}\] \[\Rightarrow \] \[\sqrt{3}=\frac{BC}{15}\] \[\Rightarrow \] \[BC=15\sqrt{3}cm\]You need to login to perform this action.
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