A) \[{{30}^{o}}\]
B) \[{{40}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{80}^{o}}\]
Correct Answer: A
Solution :
\[m\angle TRQ=m\angle RST\] [Angles in alternate segment] But\[m\angle TRQ={{30}^{o}}\] RS\[m\angle RST={{30}^{o}}\] also\[m\angle SRT={{30}^{o}}\] \[\therefore \]\[m\angle RTS={{180}^{o}}-({{90}^{o}}+{{30}^{o}})\] \[={{60}^{o}}\] \[m\angle PRS=m\angle RTS\] \[m\angle PRS={{60}^{o}}\]
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