2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-5

  • question_answer
    The least number, which when divided by 18, 27 and 36 separately leaves remainders 5, 14 and 23 respectively, is

    A)  95                                 

    B)  113

    C)  149                 

    D)         77

    Correct Answer: A

    Solution :

     The difference between the divisor and the corresponding remainder is same in each case i.e.             \[18-5=13,\,\,27-14=13,\]             \[36-23=13\] \[\therefore \]Required number             = (LCM of\[18,\,\,27\]and\[36)-13\]             \[=108-13=95\]


You need to login to perform this action.
You will be redirected in 3 sec spinner