SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-5

  • question_answer
    Through each vertex of a triangle, a line parallel to the opposite side is drawn. The ratio of the perimeter of the new triangle, thus formed, with that of the original triangle is

    A) \[3:2\]                           

    B) \[4:1\]

    C) \[2:1\]                 

    D)        \[2:3\]

    Correct Answer: C

    Solution :

                \[AQ||CB\], and\[AC||QB\] \[\therefore \]\[AQBC\], is a parallelogram \[\Rightarrow \]   \[BC=AQ\] Again, \[AR||BC\] and\[AB||RC\] \[\therefore \]\[ARCB\]is a parallelogram. \[\Rightarrow \]   \[BC=AR\Rightarrow AQ=AR\] \[\Rightarrow \]   \[AQ=AR=\frac{1}{2}QR\] Similarly, \[AB=\frac{1}{2}PR\] and             \[AC=\frac{1}{2}PQ\] \[\therefore \]Required ratio             \[=(PQ+QR+RP):(AB+BC+CA)\]             \[=2:1\]


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