A) \[{{25}^{o}}\]
B) \[{{25}^{o}}22'\]
C) \[{{25}^{o}}12'\]
D) \[{{25}^{o}}12'20''\]
Correct Answer: C
Solution :
Here,\[r=25\,\,cm\]and\[s=11\,\,cm\] \[\therefore \] \[\theta ={{\left( \frac{s}{r} \right)}^{c}}\Rightarrow \theta ={{\left( \frac{11}{15} \right)}^{c}}\] \[={{\left( \frac{11}{25}\times \frac{180}{\pi } \right)}^{o}}=\left( \frac{11}{25}\times \frac{180}{22}\times 7 \right)\] \[\Rightarrow \] \[\theta ={{\left( \frac{126}{5} \right)}^{o}}={{\left( 25\frac{1}{5} \right)}^{o}}={{25}^{o}}{{\left( \frac{1}{5}\times 60 \right)}^{o}}\] \[={{25}^{o}}12'\]
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