SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-5

  • question_answer
    If\[a=\frac{2-\sqrt{5}}{2+\sqrt{5}}\]and\[b=\frac{2+\sqrt{5}}{2-\sqrt{5}}\]. Find\[{{a}^{2}}-{{b}^{2}}\]

    A) \[44\sqrt{5}\]                

    B) \[-144\sqrt{5}\]  

    C) \[144\sqrt{5}\]   

    D)        \[-44\sqrt{5}\]

    Correct Answer: B

    Solution :

    \[a=\frac{2-\sqrt{5}}{2+\sqrt{5}}=\frac{2-\sqrt{5}}{2+\sqrt{5}}\times \frac{2-\sqrt{5}}{2-\sqrt{5}}\]             \[=\frac{{{(2-\sqrt{5})}^{2}}}{{{2}^{2}}-{{(\sqrt{5})}^{2}}}=\frac{4+5-4\sqrt{5}}{4-5}\]             \[=-9+4\sqrt{5}\] Similarly,             \[b=-(9+4\sqrt{5})\] \[\therefore \]      \[a+b=(-9+4\sqrt{5})\]             \[(-9-4\sqrt{5})=-18\]             \[a-b=(-9+4\sqrt{5})\]             \[-(-9-4\sqrt{5})=8\sqrt{5}\] \[\therefore \]      \[{{a}^{2}}-{{b}^{2}}=(a+b)(a-b)\]             \[=-18\times 8\sqrt{5}=-144\sqrt{5}\]


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