A) right-angled
B) Isosceles
C) equilateral
D) obtuse-angled
Correct Answer: B
Solution :
Since\[\angle ABD=\angle ACE\] \[\therefore \] \[{{180}^{o}}-\angle ABC={{180}^{o}}-\angle ACB\] \[\Rightarrow \] \[\angle ABC=\angle ACB\] Hence, \[\Delta ABC\] is isosceles triangleYou need to login to perform this action.
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