2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-5

  • question_answer
    If\[4{{b}^{2}}+\frac{1}{{{b}^{2}}}=2\], then the value of\[8{{b}^{3}}+\frac{1}{{{b}^{3}}}\]is

    A) \[0\]       

    B) \[1\]

    C) \[2\]                 

    D)        \[5\]

    Correct Answer: A

    Solution :

                \[{{\left( 2b+\frac{1}{b} \right)}^{3}}-3\times 2b\times \frac{1}{b}\left( 2b+\frac{1}{b} \right)\]             \[={{\left( \sqrt{6} \right)}^{3}}-6\left( \sqrt{6} \right)\]             \[=6\sqrt{6}-6\sqrt{6}=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner