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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-6

  • question_answer
    A cylinder has 'r' as the radius of the base and 'h1 as the height. The radius of base of another cylinder, having double the volume but the same height as that of the first cylinder must be equal to

    A)  \[\frac{r}{\sqrt{2}}\]                             

    B)  \[2r\]

    C)  \[r\sqrt{2}\]     

    D)         \[\sqrt{2r}\]

    Correct Answer: C

    Solution :

     If the radius of the new cylinder be R then, \[2\pi {{r}^{2}}h=\pi {{R}^{2}}h\] \[\Rightarrow \]\[{{R}^{2}}=2{{r}^{2}}\Rightarrow R=\sqrt{2r}\]


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