A) outside the triangle
B) at the right angular vertex
C) on its hypotenuse
D) within the triangle
Correct Answer: B
Solution :
Sum of angles of a triangle = \[180{}^\circ \] \[\therefore \]\[x+5+2x-3+3x+4=180{}^\circ \] \[\Rightarrow \] \[6x+6=180{}^\circ \] \[\Rightarrow \] \[6x=180-6=174{}^\circ \] \[\Rightarrow \]\[x=\frac{174}{6}=29\]
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