A) \[5{}^\circ \]
B) \[9{}^\circ \]
C) \[12{}^\circ \]
D) \[15{}^\circ \]
Correct Answer: B
Solution :
cos\[\theta \] \[=\frac{15}{17}\] \[\Rightarrow \] sec\[\theta \]=\[\frac{1}{\cos \theta }=\frac{17}{15}\] \[\therefore \]cot \[\left( 90{}^\circ -\theta \right)\]= tan \[\theta \] \[=\sqrt{{{\sec }^{2}}\theta -1}\] \[=\sqrt{\frac{289-225}{225}}=\sqrt{\frac{64}{225}}=\frac{8}{15}\]
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