A) 50 metre
B) \[75\sqrt{3}\]
C) 25\[\sqrt{3}\] metre
D) 80 metre
Correct Answer: B
Solution :
\[{{\sec }^{2}}\theta +{{\tan }^{2}}\theta =1\] \[{{\sec }^{2}}\theta +{{\tan }^{2}}\theta =\frac{7}{12}\] \[\therefore \]\[{{\sec }^{4}}\theta -{{\tan }^{4}}\theta \] \[=({{\sec }^{2}}\theta -{{\tan }^{2}}\theta )({{\sec }^{2}}\theta +{{\tan }^{2}}\theta )\] \[=1\times \frac{7}{12}=\frac{7}{12}\]
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