SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-6

  • question_answer
    If Z = 26, NET = 39, then NUT =?

    A)  50                               

    B)  53

    C)  55                               

    D)  56

    Correct Answer: C

    Solution :

     Z \[\Rightarrow \] 26 Position number in English alphabet. \[\begin{align}   & N\,\,\,\,\,\,\,\,E\,\,\,\,\,\,\,\,T \\  & \downarrow \,\,\,\,\,\,\,\,\,\,\downarrow \,\,\,\,\,\,\,\,\,\downarrow  \\  & 14\,\,\,+\,\,\,5\,\,+\,\,20=\,\,39 \\ \end{align}\] Similarly. \[\begin{align}   & N\,\,\,\,\,\,\,\,U\,\,\,\,\,\,\,\,T \\  & \downarrow \,\,\,\,\,\,\,\,\,\,\downarrow \,\,\,\,\,\,\,\,\,\downarrow  \\  & 14\,\,\,+\,\,\,21\,\,+\,\,20=\,\,55 \\ \end{align}\]


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