A) 727\[\frac{1}{2}\] cm3
B) 6272 \[\frac{2}{3}\]cm3
C) 818 \[\frac{1}{2}\] cm3
D) 718 2 cm3
Correct Answer: D
Solution :
If the radius of the base of cone be r cm, then \[\pi {{r}^{2}}=154\] \[\Rightarrow \] \[\frac{22}{7}\times {{r}^{2}}=154\] \[\Rightarrow \]\[{{r}^{2}}=\frac{154\times 7}{22}=7\times 7\] \[\Rightarrow \]\[r=7\] \[\therefore \]Volume of cone \[=\frac{1}{3}\pi \,\,{{r}^{2}}h\,\,\] \[=\frac{1}{3}\times \frac{22}{7}\times 7\times 7\times 21\] = 1078 cu. cm \[\therefore \frac{2}{3}\times \] Volume of cone \[=\frac{2}{3}\times 1078=\frac{2156}{3}\] \[=718\frac{2}{3}\] cu. Cm
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