A) \[\frac{18}{7}\]
B) \[\frac{7}{18}\]
C) \[\frac{25}{18}\]
D) \[\frac{18}{25}\]
Correct Answer: B
Solution :
\[3\,\tan \theta =4\Rightarrow \tan \theta =\frac{4}{3}\] \[\therefore \]Expression = \[\frac{4\,\sin \theta -3\cos \theta }{3\tan \theta +2\cos \theta }\] \[=\frac{4\tan \theta -3}{3\,\tan \theta +2}\] [Dividing numerator and denominator by cos \[\theta \]] \[=\frac{4\times \frac{4}{3}-3}{3\times \frac{4}{3}+2}\] \[=\frac{\frac{16}{3}-3}{4+2}=\frac{16-9}{3\times 6}=\frac{7}{18}\]
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