A) 7 hours 45 minutes
B) 4 hours
C) \[3\frac{3}{4}\]hours
D) 6 hours 45 minutes
Correct Answer: A
Solution :
Distance covered = Speed \[\times \]Time \[=48\times \left( 6+\frac{30}{60} \right)\] \[=48\times 6\frac{1}{2}=48\times \frac{13}{2}\] =312 km Case II Time taken in covering first 180km \[=\frac{180}{48}=\frac{15}{4}\]hours Remaining distance \[=312-180=132~\]km Speed = 33 kmph \[\therefore \]Time \[=\frac{132}{33}=4\] hours Total time \[=\left( \frac{15}{4}+4 \right)\] hours = 7 hours 45 minutesYou need to login to perform this action.
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