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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-8

  • question_answer
    If 10 men or 18 boys can do a work in 15 days. then the number of days required by 15 men and 33 boys to do twice the work is

    A)  9                                

    B)  36

    C)  \[4\frac{1}{2}\]                        

    D)  8

    Correct Answer: A

    Solution :

     \[\because \]10 men = 18 boys \[\therefore \] 15 men = 27 boys \[\therefore \] 15 men + 33 boys = 27 + 33 = 60 boys \[\therefore \] \[\frac{{{M}_{1}}{{D}_{1}}}{{{W}_{1}}}=\frac{{{M}_{2}}{{D}_{2}}}{{{W}_{2}}}\] \[\Rightarrow \]\[\frac{18\times 15}{1}=\frac{60\times {{D}_{2}}}{2}\] \[\therefore \]\[{{D}_{2}}=\frac{18\times 15\times 2}{60}=9\] days


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