SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-8

  • question_answer
    Minimum value of \[{{x}^{2}}+\frac{1}{{{x}^{2}}+1}-3\] is

    A)  0                                

    B)  \[-\text{ }1\]

    C) \[-\text{ }3\]                              

    D)  \[-\text{ }2\]

    Correct Answer: D

    Solution :

     \[{{x}^{2}}\underline{>}\,0\] \[\therefore \] Minimum value \[=0+\frac{1}{1}-3=-2\]


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