A) 1
B) 2
C) \[-1\]
D) 0
Correct Answer: D
Solution :
\[1+\frac{1}{{{\cot }^{2}}63{}^\circ }-{{\sec }^{2}}27{}^\circ +\] \[+\frac{1}{{{\sin }^{2}}63{}^\circ }-\cos e{{c}^{2}}27{}^\circ \] \[=1+{{\tan }^{2}}63{}^\circ -{{\sec }^{2}}27{}^\circ \] \[+\cos e{{c}^{2}}63{}^\circ -\cos e{{c}^{2}}27{}^\circ \] \[=1+{{\tan }^{2}}(90{}^\circ -27{}^\circ )-{{\sec }^{2}}27{}^\circ \] \[+\cos e{{c}^{2}}(90{}^\circ -27{}^\circ )-\cos e{{c}^{2}}27{}^\circ \] \[=1+{{\cot }^{2}}27{}^\circ -{{\sec }^{2}}27{}^\circ \] \[+{{\sec }^{2}}27{}^\circ -\cos e{{c}^{2}}27{}^\circ \] \[=1+{{\cot }^{2}}27{}^\circ -\cos e{{c}^{2}}27{}^\circ =1-1=0\] \[[\because \cos e{{c}^{2}}\theta -{{\cot }^{2}}\theta =1]\]
You need to login to perform this action.
You will be redirected in
3 sec
